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P²x² + (p²_q²)x - q^2= 0 |
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Answer» {p² - x² + (p²- q²)X-q² = 0P²x² + p²x - q²x - q² =0P²x(x+1) - q²(x+1)(P²-q²) (x+1)X = q²÷p², x= -1 p² - x² + (p²- q²)x-q² = 0 P²x² + p²x - q²x - q²=0 P²x(x+1) - q²(x+1) (P²-q²) (x+1) X= q²÷p², x= -1 |
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