1.

P(y)= y^2-y +1 if p is 0​

Answer»

0=y^2-y+1
0-1=y^2-y
-1=y^2-y
-1=y(y-1)
So,
y=-1
y-1=-1
y=-1+1
y=0



Discussion

No Comment Found

Related InterviewSolutions