1.

P(x) = 4x² -12x+9find p(1)+p(-1)​

Answer»

= 4x^2 - 12x + 9

= 4x^2 - 6X - 6x + 9

p(x) = 2x(2x - 3) - 3(2x - 3)

0 = (2x - 3)(2x - 3)

Therefore

\tt <klux>ZEROES</klux>\:are = \dfrac{3}{2} , \dfrac{3}{2}

\tt x = \dfrac{3}{2}, \dfrac{3}{2}

Hence zeroes of POLYNOMIAL are :-

\tt \dfrac{3}{2}, \dfrac{3}{2}



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