P={x:10<3x−2<34,x∈R}Q={x:28≤5X+3≤68,x∈R} The solution for P – InterviewSolution

1.	P={x:10<3x−2<34,x∈R}Q={x:28≤5X+3≤68,x∈R} The solution for P∩Q = .
Answer» $P = {x : 10 < 3 x - 2 < 34, x \in R} Q = {x : 28 \leq 5 X + 3 \leq 68, x \in R}$ The solution for $P \cap Q$ = .

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