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P,T are the centers of two circles joining internal.proove At parallel SP |
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Answer» Answer: Let the centre of the circle be O. AB = 12 CM OC = 12 cm OC ⊥ AB We know perpendicular drawn from the centre of the circle to the chord, BISECTS the chord. So, AC = 6 cm In ⃤ OCA, OC2+AC2=AO2⇒82+62=AO2⇒AO2=100⇒AO=10 Thus, AO = 10 cm Plz mark brainliest ❤️ Step-by-step explanation: |
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