P=q+r-s;q=r+s-p;r=s+p-q; and pqrs≠0 then what is the value of p/r+q/

1.	P=q+r-s;q=r+s-p;r=s+p-q; and pqrs≠0 then what is the value of p/r+q/s+r/p+s/q
Answer» <P>Substitute the values of Q and r in p By that you will get the RESULT as p=q=r=s As all are EQUAL we will get the final answer as 1÷2

P=q+r-s;q=r+s-p;r=s+p-q; and pqrs≠0 then what is the value of p/r+q/s+r/p+s/q

Answer»

<P>Substitute the values of Q and r in p

By that you will get the RESULT as

p=q=r=s

As all are EQUAL we will get the final answer as

1÷2

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P=q+r-s;q=r+s-p;r=s+p-q; and pqrs≠0 then what is the value of p/r+q/s+r/p+s/q

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