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p,q,r,s are rectangles whose ratios of breadth to length are 1:2;2:4;4:8;8:16 respectively. check whether the ratios of their areas are in proportional or not (check only P:Q :: Q:R;Q:R::R:S;R:S::P:Q). |
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Answer» Answer: 32, 48, 140, 210; (II) 6, 9, 10 and 16 Solution: (i) 32, 48, 140, 210 32 : 48 = 32/48 = 2/3 = 2 : 3 140 : 210 = 140/210 = 2/3 = 2 : 3 So, 32 : 48 = 140 : 210 Therefore, 32, 48, 140, 210 are in proportion. i.e., 32 : 48 :: 140 : 210 Step-by-step explanation: (ii) 6, 9, 10 and 16 6 : 9 = 6/9 = 2/3 = 2 : 3 10 : 16 = 10/16 = 5/8 = 5 : 8 Since, 6 : 9 ≠ 10 : 16 therefore, 6, 9, 10 and 16 are not in proportion. 2. The numbers 8, x, 9 and 36 are in proportion. Find x. Solution: The numbers 8, x, 9 and 36 are in proportion ⇒ 8 : x = 9 : 36 ⇒ x × 9 = 8 × 36, [Since, the PRODUCT of the means = the product of the extremes] ⇒ x = (8 × 36)/9 ⇒ x = 32 3. If x : 15 = 8 : 12; find the VALUE of x. Solution: ⇒ x × 12 = 15 × 8, [Since, the product of the extremes = the product of the means] ⇒ x = (15 × 8)/12 ⇒ x = 10 4. If 4, x, 32 and 40 are in proportion, find the value of x. Solution: 4, x, 32 and 40 are in proportion, i.e., 4 : x :: 32 : 40 Now, product of extremes = 4 × 40 = 160 And product of means = x × 32 We know that in a proportion product of extremes = product of means i.e., 160 = x × 32 If we multiply 32 by 5, we get 160 i.e., 5 × 32 = 160 So, x = 5 |
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