P is a variable point on the line `L=0` . Tangents are drawn to the circles `x^(2)+y^(2)=4` from P to touch it at Q and R. The parallelogram PQSR is completed. If `P-= (6,8)`, then the area of `Delta QRS` isA. `(3sqrt(6))/(25)` sq. unitsB. `(3sqrt(24))/(25)` sq. unitsC. `(48sqrt(6))/(25)` sq. unitsD. `(192sqrt(6))/(25)` sq. units

P is a variable point on the line `L=0` . Tangents are drawn to the ci

1.	P is a variable point on the line `L=0` . Tangents are drawn to the circles `x^(2)+y^(2)=4` from P to touch it at Q and R. The parallelogram PQSR is completed. If `P-= (6,8)`, then the area of `Delta QRS` isA. `(3sqrt(6))/(25)` sq. unitsB. `(3sqrt(24))/(25)` sq. unitsC. `(48sqrt(6))/(25)` sq. unitsD. `(192sqrt(6))/(25)` sq. units
Answer» Correct Answer - 4 `P -= (6,8)` Thereforem the equation of QR (chord of contact ) is `6x+8y=4` or `3x+4y-2=0 ` `:. PM =(48)/(50` and `PQ =sqrt(96)` `QM =sqrt(96-(48^(2))/(25))=sqrt((96)/(25))` `:. QR = 2 sqrt((96)/(25))` `:. ` Area of `Delta PQR =(1)/(2) xx PM xx QR =(192 sqrt(6))/(25)` PQRS is a rhombus. Therefore, Area of `Delta RS =` Area of `Delta PQR = (192sqrt(6))/(25)`

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