P is a point on the axis of the parabola y2=4ax; Q, and R are the extremities of its latus rectum and A is its vertex. If PQR is an equilateral triangle lying within the parabola and ∠AQP=θ, then cosθ=

P is a point on the axis of the parabola y2=4ax; Q, and R are the extr

1.	P is a point on the axis of the parabola y2=4ax; Q, and R are the extremities of its latus rectum and A is its vertex. If PQR is an equilateral triangle lying within the parabola and ∠AQP=θ, then cosθ=
Answer» $P$ is a point on the axis of the parabola $y^{2} = 4 a x$ ; $Q,$ and $R$ are the extremities of its latus rectum and $A$ is its vertex. If $P Q R$ is an equilateral triangle lying within the parabola and $∠ A Q P = θ$ , then $cos θ =$

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P is a point on the axis of the parabola y2=4ax; Q, and R are the extremities of its latus rectum and A is its vertex. If PQR is an equilateral triangle lying within the parabola and ∠AQP=θ, then cosθ=

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