P(E | F)=\frac{P(E \cap F)}{P(F)}=\frac{\frac{1}{6}}{\frac{3}{4}}= – InterviewSolution

1.

P(E | F)=\frac{P(E \cap F)}{P(F)}=\frac{\frac{1}{6}}{\frac{3}{4}}=

Answer»

P(E|F) = P( E INTERSECTION F)/P(F) = (1/6)/(3/4) = 4/(3×6) = 2/(3×3) = 2/9

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