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p \cdot T \frac { 1 } { \operatorname { log } _ { 3 } 60 } + \frac { 1 } { \operatorname { log } _ { 4 } 60 } + \frac { 1 } { \operatorname { log } _ { 5 } 60 } = 1 |
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Answer» how it comes explane which part u don't understand second step these are properties of log, i have only used that ok thanks Madam or sir |
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