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P can do work in 20 days and Q can do the same in 40 days. If they start the work together and P leaves that work 10 days before completion. In how many days the work will be finished?1. 15 days2. 20 days3. 30 days4. 10 days |
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Answer» Correct Answer - Option 2 : 20 days Given: P can do a piece of work = 20 days Q can do a piece of work = 40 days P leaves that work 10 days before completion Concept used: Total work = LCM Formula used: Efficiency = Work/Time Calculations: Total work = LCM = 40
Let the work finishes in x days So, Time in which P works = (x – 10) Work done by P in (x – 10) days = 2 × (x – 10) Work done by Q in x days = 1 × x = x Now, ⇒ 2(x – 10) + x = 40 ⇒ 2x – 20 + x = 40 ⇒ 3x = 60 ⇒ x = 20 days ∴ Time in which the total work has completed is 20 days |
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