1.

P and Q can do a piece of work in 10 days while Q and R can do the same work in 12 days and R and P in 15 days. They all work together for 6 days. How long will P take to finish the remaining work?1. 8 days2. 6 days3. 9 days4. 10 days

Answer» Correct Answer - Option 2 : 6 days

Given:

P and Q can do a piece of work = 10 days

Q and R can do the same work = 12 days

R and P can do a piece of work = 15 days

Concept used:

Total work = LCM

Formula used:

Efficiency = Work/Time

Calculation

Total work = LCM = 60

Person

Time

Total work

Efficiency

P + Q

10 days

60

60/10 = 6

Q + R

12 days

60

60/12 = 5

R + P

15 days

60

60/15 = 4


Total efficiency of P + Q + Q + R + R + P = 6 + 5 + 4 = 15

⇒ 2(P + Q + R) = 15

⇒ P + Q + R = 15/2

P, Q, and R work together 6 days

Work completed by P, Q, and R together in 6 days = (15/2) × 6 = 45

Remaining work = 60 – 45 = 15

Efficiency of P = Efficiency (P + Q + R) – Efficiency of (Q + R)

⇒ (15/2) – 5 = 5/2 = 2.5

Time taken by P to complete the remaining work = 15/2.5 = 6 days

Time taken by P to complete the remaining work is 6 days



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