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P and Q are two points on a uniform ring of resistance R. The equivalent resistance between P and Q is |
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Answer» Solution :Resistance of SECTION PSQ `R_(1)=(R )/(2pir).r theta=(R theta)/(2PI)` Resistance of section PTQ  `R_(2)=(RR(2pi-theta))/(2pir)rArr (R(2pi-theta))/(2pi)` As `R_(1) and R_(2)` are in parallel `"So, "R_("eq")=(R_(1)R_(2))/(R_(1)+R_(2))=(Rtheta(2pi-theta))/(4pi^(2))` |
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