P and Q are the mid- points of the sides CA and CB respectively of a ∆ ABC, right angled at C. Prove that: (1) 4AQ^2 = 4AC^2 + BC^2 (2) 4BP^2 = 4BC^2 + AC^2 (3) (4AQ^2 + BP^2) = 5AB2

P and Q are the mid- points of the sides CA and CB respectively of a �

1.	P and Q are the mid- points of the sides CA and CB respectively of a ∆ ABC, right angled at C. Prove that: (1) 4AQ^2 = 4AC^2 + BC^2 (2) 4BP^2 = 4BC^2 + AC^2 (3) (4AQ^2 + BP^2) = 5AB2
Answer» P and Q are the mid- points of the sides CA and CB respectively of a ∆ ABC, right angled at C. Prove that: (1) 4AQ^2 = 4AC^2 + BC^2 (2) 4BP^2 = 4BC^2 + AC^2 (3) (4AQ^2 + BP^2) = 5AB2