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P = A sin (Bt + Ct2) + x Here t is time and x is length. The dimensions of AB/Cwill be[M°LT'][MºLT-2G22[MLT-1[MºL2T-1] |
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Answer» ensions of AB/C is [M⁰LT]THEREFORE, option (1) is correct.Explanation:Given:EquationWhere t is time and X is lengthTo find out:Dimensions of AB/CSolution:Since x is length therefore, P and will also have the dimensions of lengthAlso because the sine of SOMETHING will be a dimensionless quantityTherefore, The dimensions of A will be that of the dimensions of length i.e. [L]Also the QUANTITY whose sine is been TAKEN should be dimensionlessTherefore, B will have dimensions of inverse of time i.e. [T⁻¹]And C will have dimensions of inverse of square of time i.e. [T⁻²]Thus,Dimensions of AB/C= [L][T⁻¹]/[T⁻²]= [LT]= [M⁰LT]Hope this answer is helpful.Know More:Q: If x=a+bt+ct2 where x is in metres and t is in seconds.What is the unit of c? Click Here: brainly.in/question/2774589 |
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