P 72:५0" 222 10l S a2 AT AR(&) 22 («4 2...८८ 5 – InterviewSolution

1.

P 72:५0" 222 10l S a2 AT AR(&) 22 («4 2...८८ 5

Answer»

sin3x=sin60cos30+cos60sin30sin3x=(√3/2)*(√3/2)+(1/2)*(1/2)=3/4 + 1/4=4/4=1

Sin3x=1Sin3x=sin903x=90x=90/3=30

Option b is correct

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