Saved Bookmarks
| 1. |
Oxygen is prepared by catalytic de-composition of potassium chlorate (). Decomposition of potassium chlorate gives potassium chloride (KCl) and oxygen (). If 2.4 mole of oxygen is needed for an experiment, how many grams of potassium chlorate must be decomposed? (At mass K = 39, Cl = 35.5, O = 16) |
|
Answer» alytic decomposition reaction is carried out in the presence of CATALYST CALLED CATALYTIC decomposition reaction.Potassium dichlorate undergoes decomposition reaction to form potassium chloride and OXYGEN gas.Molecular weight of From the above reaction,For 3 moles of , we need For 2.4 moles of , we need:== 196 g of |
|