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Oxygen at 1 atmosphere and `0^(@)C` has a density of `1.4290 g L^(-1)`. Find the rms speed of oxygen molecule. |
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Answer» `P = 1 atm = 101.3 xx 10^(3) Pa` `d = 1.4290 g L^(-1) = 1.4290 kg m^(-3)` We know that, `c = sqrt((3P)/(d)) = sqrt((3 xx 101.3 xx 10^(3))/(1.4290)) = 461.15 ms^(-1)` |
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