1.

Out of the ions Zn^(2+), Ni^(2+) and Cu^(3+) (At. Nos. Zn=30 Ni=28, Cr=24)

Answer»

only `Zn^(2+)` is COLOURLESS and `Ni^(2+)` and `Cr^(3+)`are coloured
all three are colourless
all three are coloured
only `Ni^(2+)` is coloured and `Zn^(2+)` and `Cr^(3+)` are colourless

Solution :`{:("Ion","Electronic","Unpaired"),(,"CONFIGURATION","electrons"),(Zn^(2+),3D^(10),0),(Ni^(2+),3d^(8),2),(Cu^(3+),3d^(8),2):}`
`Ni^(2+) and Cu^(3+)` have partly FILLED d - orbital thus coloured but `Zn^(2+)` has completely filled d- orbital, thus colourless.


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