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Out of following equations, which has 3 as solutionx2+2x-15x ,,x2-x-6=0,, x2+x+6=0,, x2-x+6=0,, x2+x+6=0 |
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Answer» Step-by-step EXPLANATION:
discriminant = b²-4ac a=1 , b=2 , c = -15 d = (2)² - 4(1)(-15) d = 4 - (-60) d = 4 + 60 = 64 d = 64
therefore this equation have real and district solutions
discriminant = b² - 4ac a=1, b = -1 , c = -6 d = (-1)² - 4(1)(-6) d = 1 - (-24) d = 1 + 24 = 25 d = 25 therefore the equation have real and DISTINCT solutions.
discriminant = b² - 4ac a=1, b=1, c=6 d= (1)² - 4(1)(6) d = 1 - 24 d = -23 therefore the equation doesn't have real equations.
discriminant = b² - 4ac a= 1, b= -1 , c = 6 d = (-1)² - 4(1)(6) d = 1 - 24 d = -23 therefore the equation doesn't have any real equations. hope it's helpful |
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