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Osmotic pressure of a solution containing 7 g of a protein per 100 mL of solution is 25 mm Hg at 310 K. Calculate the mass of the protein. (R=0.0821L atm K^(-1)mol^(-1))

Answer»


SOLUTION :`W_(B)=7g, V=100mL=0.1 L, pi=25" mm of Hg"=25/760=0.032895 atm`
`T=310 K, R=0.0821" L atm K"^(-1)mol^(-1), M_(B)=?`
` M_(B)=(W_(B)xxRxxT)/(pixxV)=((7g)xx(0.021"L atm K"^(-1)mol^(-1))xx(310 K))/((0.032895" atm")xx(0.1L))=54159.29" g mol"^(-1)`


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