os. sn-teaue of 2oo A-1Board Term-1, 2012, Set – InterviewSolution

1.

os. sn-teaue of 2oo A-1Board Term-1, 2012, Set

Answer»

Given Sin A = sqroot(3)/2 = P/H

To find B use pythagoras theoramB*B = 2*2 - sqroot(3)*sqroot(3)B*B = 4 - 3 = 1B = 1

Cot A = B/P = 1/sqroot(3)

Thus, 2Cot^2 A - 1 = 2*1/3 - 1 = 2/3 - 1= - 1/3

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