ORProve that the sum of the squares of the sides of a rhombus is equal

1.	ORProve that the sum of the squares of the sides of a rhombus is equal to the sum of the squaresof its diagonals, ie AB+BC+CD+AD = ACBD (see figure)283
Answer» Answer: GIVEN :- A rhombus ABCD whose diagonals AC and BD INTERSECT at O. To Prove :- ( AB² + BC² + CD² + DA² ) = ( AC² + BD² ). ➡ We know that the diagonals of a rhombus BISECT each other at right angles. ==> 4AB² = ( AC² + BD² ) .

ORProve that the sum of the squares of the sides of a rhombus is equal to the sum of the squaresof its diagonals, ie AB+BC+CD+AD = ACBD (see figure)283

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GIVEN :- A rhombus ABCD whose diagonals AC and BD INTERSECT at O. To Prove :- ( AB² + BC² + CD² + DA² ) = ( AC² + BD² ). ➡ We know that the diagonals of a rhombus BISECT each other at right angles. ==> 4AB² = ( AC² + BD² ) .

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ORProve that the sum of the squares of the sides of a rhombus is equal to the sum of the squaresof its diagonals, ie AB+BC+CD+AD = ACBD (see figure)283​

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ORProve that the sum of the squares of the sides of a rhombus is equal to the sum of the squaresof its diagonals, ie AB+BC+CD+AD = ACBD (see figure)283