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ORProve that n a rishi triangle, the square on the hapomm ise gw:amoitha |
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Answer» Given:triangle ABC is a right triangle right angled at B RTP: AC^2= AB^2+AC^2 CONSTRUCTION :Draw BD_|_ AC Proof:triangle ADB~triangle ABC => AD÷AB=AB÷AC AC.AD=AB^2 ………….. (1) Also triangle BDC~triangle ABC CD÷BC=BC÷AC CD.AC=BC^2 ………….. (2) On adding (1) & (2) AD.AC+CD.AC=AB^2+BC^2 AC (AD+CD)=AB^2+BC^2 AC.AC=AB^2+BC^2 ∴AC²=AB²+BC² |
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