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ORIf st.necos6, then find the value of 2tan+ cos 9 |
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Answer» sinθ = cosθtanθ= 1So,θ= 45°So,2tanθ+ cos²θ2tan(45°) + cos²(45°)2 × 1 + 1/(√2)²2 + 1/25/2 |
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