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Organic compound ‘A’ of molecular formula C₂H₆O liberates hydrogen gas with sodium metal. ‘A’ gives ‘B’ of formula C₄H₁₀O, when it reacts with concentrated H₂SO₄ at 413K. At 443K with concentrated H₂SO₄ ‘A’ gives compound ‘C’ of formula C₂H₄. This compound ‘C’ decolourises bromine water. What are ‘A’, ‘B’ and ‘C’? |
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Answer» udent,◆ Answer - COMPOUND A => EthanolCompound B => Diethyl etherCompound C => Ethene◆ Reactions -Ethanol (A) liberates hydrogen gas with sodiummetal.2C2H5-OH + 2NA --> 2C2H5-ONa + H2Ethanol (A) reacts with concentrated H₂SO₄ at 413K to give DIMETHYL ether (B).2C2H5-OH --> C2H5-O-C2H5 + H2OEthanol (A) reacts with concentrated H₂SO₄ at 443K to give ethene (C).C2H5-OH --> CH2=CH2 + H2OEthene (C) reacts with bromine water to form ethyl dibromide which is colourless.CH2=CH2 + Br2 --> Br-CH2-CH2-BrThanks dear... |
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