1.

Orbital acceleration of an electron is ………..

Answer»

`(pi^(2)N^(2)h^(2))/(2m^(2)r^(3))`
`(n^(2)h^(2))/(4pi^(2)m^(2)r^(3))`
`(4n^(2)h^(2))/(pi^(2)m^(2)r^(3))`
`(n^(2)h^(2))/(pi^(2)m^(2)r^(3))`

Solution :Angular momentum of electron in `n^(th)` orbit,
`MVR=(nh)/(2pi)`
`:.V=(nh)/(2pimr)`
`:.(v^(2))/(r)=(n^(2)h^(2))/(4pi^(2)m^(2)r^(3))`
`:.a_(C)=(n^(2)h^(2))/(4pi^(2)m^(2)r^(3))`
[ `:.(v^(2))/(r)=` centripetal acceleration `a_(c)` ]


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