1.

\operatorname{tg} 3 x=\sin 45^{\circ} \cos 45^{\circ}+Sin 3o then the Value of x

Answer»

Tan3x = sin45°cos45° + sin30° = (1/√2)×(1/√2) + 1/2 = 1/2 + 1/2 = 1tan 45° = 1so, 3x = 45⇒x = 15°



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