\operatorname { tan } 70 ^ { \circ } = \operatorname { tan } 20 ^ { \c – InterviewSolution

1.	\operatorname { tan } 70 ^ { \circ } = \operatorname { tan } 20 ^ { \circ } + 2 \operatorname { tan } 50 ^ { \circ }
Answer» As we all know,According to the trigonometric identity,tan70=tan(20+50)tan70=(tan20+tan50)/1-tan20tan50tan70-tan20tan50tan70=tan20+tan50Also tan70tan20=tan70cot70=1Hencetan70-tan50=tan20+tan50So tan70=tan20+2tan50

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