\operatorname { tan } ^ { - 1 } \frac { 63 } { 16 } = \operatorname { – InterviewSolution

1.	\operatorname { tan } ^ { - 1 } \frac { 63 } { 16 } = \operatorname { sin } ^ { - 1 } \frac { 5 } { 13 } + \operatorname { cos } ^ { - 1 } \frac { 3 } { 5 }
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