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\operatorname { sin } ^ { - 1 } \frac { 3 } { 5 } + \operatorname { sin } ^ { - 1 } \frac { 8 } { 17 } = \operatorname { cos } ^ { - 1 } \frac { 36 } { 85 } |
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Answer» sin^(-1)(3/5)=tan^(-1)(3/4)sin^(-1)(8/17)=tan^(-1)(8/15)tan^(-1)(3/4)+tan^(-1)(8/15)=tan^(-1)((3/4+8/15)/(1-3/4*8/15))=tan^(-1)((77/60)/(9/15))=tan^(-1)(77/36)=cos^(-1)(36/85) |
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