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\operatorname sin ^ - 1 \frac 3 5 %2B \operatorname sin ^ - 1 \frac 6 17 = \operatorname sin ^ - 1 \frac 77 85 |
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Answer» sin^-1(3/5) + sin^-1(8/17) = sin^-1{3/5√[1 - (8/17)^2] + 8/17√[1 - (3/5)^2} =sin^-1[ 3/5 *15/17 + 8/17 * 4/5 ] =sin^-1[ 45/85 + 32/85 ] = sin^-1[ 77/85 ] |
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