\operatorname { sin } ^ { - 1 } ( 2 x \sqrt { 1 - x ^ { 2 } } ) = 2 \o – InterviewSolution

1.

\operatorname { sin } ^ { - 1 } ( 2 x \sqrt { 1 - x ^ { 2 } } ) = 2 \operatorname { sin } ^ { - 1 } x , - \frac { 1 } { \sqrt { 2 } } \leq x \leq \frac { 1 } { \sqrt { 2 } }

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