\operatorname sec 41 ^ \circ \cdot \operatorname sin 49 ^

1.	\operatorname sec 41 ^ \circ \cdot \operatorname sin 49 ^ \circ %2B \operatorname cos 49 ^ \circ \cdot \operatorname cosec 41 ^ \circ - \frac 2 \sqrt 3
Answer» sec 41= 1/cos 41now cos41= sin(90-41)= sin49now cosec 41= 1/sin41nowsin41= cos(90-41)= cos49 now tan 20= cot(90-20)=cot70now after putting all values1+1-(2/√3*√3)2-20thanks

\operatorname sec 41 ^ \circ \cdot \operatorname sin 49 ^ \circ %2B \operatorname cos 49 ^ \circ \cdot \operatorname cosec 41 ^ \circ - \frac 2 \sqrt 3

Answer»

sec 41= 1/cos 41now cos41= sin(90-41)= sin49now cosec 41= 1/sin41nowsin41= cos(90-41)= cos49

now tan 20= cot(90-20)=cot70now after putting all values1+1-(2/√3*√3)2-20thanks