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\operatorname { log } ( m + n ) = \operatorname { log } m + \operatorname { log } n , \text { show that } n = \frac { m } { m - 1 } |
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Answer» Log(m+n)= logm+ logn log(m+n) = log(mn). [ loga+logb =log ab] log on both sides geys cancelthen, m+n = mn => m= mn -n=> m = n(m-1)=> n = m/m-1 [proved] |
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