1.

\operatorname { lim } _ { x \rightarrow \frac { \pi } { 6 } } \frac { \operatorname { cot } ^ { 2 } x - 3 } { \operatorname { cosec } x - 2 }

Answer»

by putting x=pie/6 we will get 0/0 form so using L'hospital rulelim x->pie/6 -2cotxcosec^2x/-cosecxcotx=lim x->pie/6 2cosecx=2(2)=4



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