\operatorname lim _ u \rightarrow 1 ^ 1 \frac \operatorn – InterviewSolution

1.	\operatorname lim _ u \rightarrow 1 ^ 1 \frac \operatorname sin ^ 2 \alpha - \operatorname sin ^ 2 \beta \alpha ^ 2 - \beta ^ 2
Answer» lim α→β (sin²α-sin²β/α²-β²)we are getting 0/0 form so using L hospital rulelim α→β(2sinα/2α)=sinβ/β

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