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\operatorname { cosec } \theta = \frac { 3 } { 2 } , \text { then } 2 ( \operatorname { cosec } ^ { 2 } \theta + \operatorname { cot } ^ { 2 } \theta ) |
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Answer» cosecx=3/2now cot^2x-cosec^2x=1so cotx=root(1+9/4)=root(13)/2so cosec^2x+cot^2x=(3/2)^2+(root(13)/2)^2 =9/4+13/4=22/4so 2(cosec^2x+cot^2x)=2*22/4=11 |
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