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Only `N_2,CO and CO_2` gases remain after 0.72 gm of carbon is treated with one litre of air at `27^@C and 4.92` atm pressure.Assume air composition `O_2=20%,N_2=79%,and CO_2=1%` (by volume).The heat evolved (in Kcal) under constant pressure is : Given : `C+OtoCO_2, DeltaH=-100` Kcal/mol `C+1/2O_2toCO, DeltaH=-25` Kcal/mol |
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Answer» Correct Answer - Heat evolved = 3 kcal `n_(air)=(4.92xx1)/24.6=0.2` mol `n_(O_2)=0.2xx0.2=0.04 mol, n_c=0.72/12` `{:(,C" "+,1/2O_2,toCO),("initial mole",0.06,0.04," " 0),("final mole",0,0.01," "0.06):}` `{:(,CO" "+,1/2O_2,toCO_2),("initial mole",0.06,0.01," " 0),("final mole",0.04,0," "0.02):}` Heat evolved =`0.04xx25+0.02xx100=1+2=3 kcal` |
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