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⇔⇔⇔→Only for special ranked← ⇔⇔⇔If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m?↓→Content quality required←↑Thanks :)

Answer»

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\large\mathsf\red{Q \ - \ What \ is \ Mean \ ?}

\mathsf\blue{Mean \ is \ the \ total \ of \ all \ values \ divided}
\mathsf\blue{by \ the \ number \ of \ values.}

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\large\mathsf\green{Given \ -}

\mathsf{x \ is \ mean \ of \ m \ and \ 9.}

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\mathsf{x \ = \ (m + 9) / 2}

\mathsf{Also,}

\mathsf{y \ is \ the \ mean \ of \ 2m \ and \ 15.}

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\mathsf{y \ = \ (2m + 15)/2}

\mathsf{Also,}

\mathsf{z \ is \ the \ mean \ of \ 3m \ and \ 18.}

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\mathsf{z \ = \ (3m + 18)/2}

\mathsf{Now,}

\mathsf{x + y + z \ -}

\mathsf{= \ (m + 9) / 2 + (2m + 15)/2 + (2m + 15)/2}

\mathsf{= \ (6m + 42)/2}

\mathsf{= \ 3m + 21}

\mathsf{Average \ of \ x, \ y \ and \ z}

\mathsf{= \ (3m + 21)/3}

\large\mathsf\green{= \ m + 7}

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