U can SOLVE like this. INNER radius of hemispherical bowl = 5 CMThickness of the bowl = 0.25 cmOuter radius (r) of hemispherical bowl = (5 + 0.25) cm= 5.25 cmOuter CSA of hemispherical bowl = 2πr2= 2 * 22/7* (5.25)2= 173.25 cm2
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