One says give me a 100 I will become twice as rich as you.the other re

1.	One says give me a 100 I will become twice as rich as you.the other replies give me 10 and I will become 6 times as rich as you. Tell me the amount of their respectively capital
Answer» ANSWER: Let one FRIEND has capital amount= ₹ x and other friend has capital amount =₹ y . ATQ x + 100 = 2(y − 100) x + 100 = 2y − 200 x - 2y = -200 -100 x − 2y = −300……………….(1) and 6(x − 10) = (y + 10) 6x − 60 = y + 10 6x - y = 10 +60 6x − y = 70…………………….(2) By using elimination method On Multiplying equ (2) by 2, 12x − 2y = 140……………….(3) On Subtracting equation (1) from equation (3), 12x − 2y - (x − 2y ) = 140 - (-300) 12x - 2y - x + 2y = 140 + 300) 11x = 140 + 300 11x = 440 x = 440/11 x = 40 Put x = 40 in equation (1), x − 2y = −300 40 − 2y = −300 40 + 300 = 2y 2y = 340 y = 340/2 y = 170 Hence, the amount of first friend capital is ₹ 40 and the amount of second friend capital is ₹ 170. HOPE THIS WILL HELP YOU……….

One says give me a 100 I will become twice as rich as you.the other replies give me 10 and I will become 6 times as rich as you. Tell me the amount of their respectively capital

Answer»

Let one FRIEND has capital amount= ₹ x and other friend has capital amount =₹ y .

ATQ

x + 100 = 2(y − 100)

x + 100 = 2y − 200

x - 2y = -200 -100

x − 2y = −300……………….(1)

and 6(x − 10) = (y + 10)

6x − 60 = y + 10

6x - y = 10 +60

6x − y = 70…………………….(2)

By using elimination method

On Multiplying equ (2) by 2,

12x − 2y = 140……………….(3)

On Subtracting equation (1) from equation (3),

12x − 2y - (x − 2y ) = 140 - (-300)

12x - 2y - x + 2y = 140 + 300)

11x = 140 + 300

11x = 440

x = 440/11

x = 40

Put x = 40 in equation (1),

x − 2y = −300

40 − 2y = −300

40 + 300 = 2y

2y = 340

y = 340/2

y = 170

Hence, the amount of first friend capital is ₹ 40 and the amount of second friend capital is ₹ 170.

HOPE THIS WILL HELP YOU……….