1.

One pink solid (X) has the formula `CoCl_3. 5NH_3. H_2O`.A solution of this salt (X) in water is also pink and precipitates 3 moles AgCl on treatment with silver nitrate solution..When the pink solid (X) is heated, it loses 1 mole `H_2O` to yield a purple solid (Y) with the same molar ratio of `NH_3:Cl:Co`.The purple solid releases two of its chlorides rapidly on dissolution and after treatment with `AgNO_3` solution.The coordination number of cobalt in complexes (X) and (Y) is six. The IUPAC name of pink (X) and purple (Y) complexes respectively are :A. Tetraamminechloridoaquacobalt(III) chloride and pentaamminechloridocobalt(III) chlorideB. Pentaammin echloridocarbalt(III) chloride and pentaammineaquacobalt (III) chlorideC. Pentaammineaquacobalt(III) chloride and pentaamminechloridocobalt(III)chlorideD. Pentaammineaquacobaltate(III) chloride and pentaamminechloridocobaltate (III) chloride

Answer» Correct Answer - C
`underset(1:5:1)([Co(NH_3)_5H_2O])Cl_3("pink")overset(aq.)hArr[Co(NH_3)_5H_2O]^(3+)+3Cl^(-)`
`3Ag^(+)+3 Cl^(-)to3AgCldarr`(white)
The following complex is obtained on heating and losing 1 mole of `H_2O`
`underset(1:5:1)([Co(NH_3)_5Cl]Cl_2)("purple")overset(aq.)hArr[Co(NH_3)_5Cl]^(2+)+2Cl^(-)`
`2Ag^(+)+2Cl^(-)to2AgCldarr`(white)
So, pink (X) is `[Co(NH_3)_5(OH_2)]Cl_3` and IUPAC name would be pentaammineaquacobalt(III) chloride and purple (Y) is `[Co(NH_3)_5Cl]Cl_2` and IUPAC name would be pentaamminechloridocobalt(III)chloride.


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