One-one onto (gof)-1 = f-1og-1 – InterviewSolution

1.

One-one onto (gof)-1 = f-1og-1

Answer»

To prove (gof)^-1 = f^-1og^-1

(f^-1og^-1) 0 (gof)

= (f^-1og^-1)(og) of

= (f^-1o(g^-1og)) of

= (f^-1oI_B) of = I_A

Hence, (gof) 0 (f^-1og^-1) = I_C

Hence, (gof)^-1 = f^-1og^-1

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