One of the two digits of a two digit number is three times the other d

1.	One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?Plz ans this question fast with proper explanation
Answer» SOLUTION : $\bf{\orange{\underline{\underline{\bf{Given\::}}}}}$ ONE of the TWO digits of a two digit number is three TIMES the other digit. If you interchange the digits of the two - digit number and add the resulting number to the original number, you get 88. $\bf{\orange{\underline{\underline{\bf{To\:find\::}}}}}$ The original number. $\bf{\orange{\underline{\underline{\bf{Explanation\::}}}}}$ Let the one's place be r Let the ten's place be 3r $\bf{\underline{\sf{The\:Original\:number\:=10(3r)+r}}}}\\\bf{\underline{\sf{The\:Reversed\:number\:=10(r)+3r}}}}$ A/q $\mapsto\sf{10(3r)+r+10r+3r=88}\\\\\mapsto\sf{30r+r+13r=88}\\\\\mapsto\sf{44r=88}\\\\\mapsto\sf{r=\cancel{\dfrac{88}{44} }}\\\\\mapsto\sf{\red{r=2}}$ Thus; $\sf{The\:original\:number=10(3r)+r}\\\\\sf{The\:original\:number=10(3*2)+2}\\\\\sf{The\:original\:number=10(6)+2}\\\\\sf{The\:original\:number=60+2=\red{62}}$

One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?Plz ans this question fast with proper explanation

Answer»

SOLUTION :

$\bf{\orange{\underline{\underline{\bf{Given\::}}}}}$

ONE of the TWO digits of a two digit number is three TIMES the other digit. If you interchange the digits of the two - digit number and add the resulting number to the original number, you get 88.

$\bf{\orange{\underline{\underline{\bf{To\:find\::}}}}}$

The original number.

$\bf{\orange{\underline{\underline{\bf{Explanation\::}}}}}$

Let the one's place be r

Let the ten's place be 3r

$\bf{\underline{\sf{The\:Original\:number\:=10(3r)+r}}}}\\\bf{\underline{\sf{The\:Reversed\:number\:=10(r)+3r}}}}$

A/q

$\mapsto\sf{10(3r)+r+10r+3r=88}\\\\\mapsto\sf{30r+r+13r=88}\\\\\mapsto\sf{44r=88}\\\\\mapsto\sf{r=\cancel{\dfrac{88}{44} }}\\\\\mapsto\sf{\red{r=2}}$

Thus;

$\sf{The\:original\:number=10(3r)+r}\\\\\sf{The\:original\:number=10(3*2)+2}\\\\\sf{The\:original\:number=10(6)+2}\\\\\sf{The\:original\:number=60+2=\red{62}}$

One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?Plz ans this question fast with proper explanation

SOLUTION :

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