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One morning a big circus arrived in the Ramleela maidan at Delhi. The arrival of the circus was seen in the morning at 08:00 AM by Gopal. He passed this information on 08:15 to 2 other residents of the city. Each of these 2 people then informed the other 2 residents at 08:30, and again at 08:45, they reported the arrival of the circus every 2 to other uninformed residents This chain continued the same way till 12:00 PM. By 12:00 PM enough people were informed about the arrival of the circus.Answer the following equations:i. By 12:00 PM total how many people were informed about the arrival of the circus?a. 131000 b. 131017 c.141000 d.65536ii. By 10:00 AM total how many people were informed about the arrival of the circus?a. 511 b. 256 c. 300 d.500iii. From 10:00 AM to 11:00 AM how many people were informed about the circus?a. 8000 b.7000 c.7680 d.7936iv. What are the three terms between 16 and 256?a. 64 , 32,128 b.16 , 32,256 c.32 , 64,128 d.16 ,32, 64v. At 10:30 AM how many people were informed about the circus?a. 512 b.1024 c.2048 d.2047 |
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Answer» Given : The arrival of the CIRCUS was seen in the morning at 08:00 AM by GOPAL. they reported the arrival of the circus every 2 to other uninformed residents To find : By 12:00 PM total how many people were informed about the arrival of the circus? Solution: 08:00 1 08:15 2 08:30 4 08:45 8 09:00 16 09:15 32 09:30 64 09:45 128 10:00 256 10:15 512 10:30 1024 10:45 2048 11:00 4096 11:15 8192 11:30 16384 11:45 32768 12:00 65536 Total = 131071 This is an GP a = 1 r = 2 from 8 AM to 12 PM n = 17 S = a(rⁿ - 1)/(r -1 ) = 1(2¹⁷ - 1) = 1,31,071 by 10 AM n = 9 2⁹ - 1 = 511 10:00 AM to 11:00 AM 2¹³ - 1 - (2⁹ - 1 ) = 7,680 three terms between 16 and 256 32 , 64 , 128 At 10:30 AM = 2¹¹ - 1 = 2047 Learn More: if the sum of three consecutive numbers in a geometric progression ... Four terms are in G.P. sum of first TWO term is 8 and sum of last two ... |
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