Saved Bookmarks
| 1. |
One mole of NaCl (s) on melting absorbed 30.5 kJ of heat and its entropy is increased by 28.8 JK^(-1). The melting point of NaCl is |
|
Answer» 1059 K Given that : `DeltaH=30.5 kJ mol^(-1)` `DeltaS=28.8 JK^(-1)=28.8xx10^(-3)kJ K^(-1)` By USING `DeltaS=(DeltaH)/(T)=(30.5)/(28.8xx10^(-3))=1059 K`. |
|