One mole of H2O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 50% of water (by mass) reacts with CO according to the equation, H2O(g) + CO(g) H2(g) + CO2(g) Calculate the equilibrium constant for the reaction

One mole of H2O and one mole of CO are taken in 10 L vessel and heated

1.	One mole of H2O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 50% of water (by mass) reacts with CO according to the equation, H2O(g) + CO(g) H2(g) + CO2(g) Calculate the equilibrium constant for the reaction
Answer» wer:-The GIVEN reaction is: H2O (g) + CO (g) ↔ H2 (g) + CO2 (g)Initial Concentration: 1/10 M 1/10 M 0 0At EQUILIBRIUM 1-0.4/10 M 1-0.4/10 M 0.4/10M 0.4/10M = 0.06M 0.06M 0.04M 0.04MTherefore, the equilibrium CONSTANT for the reaction, ' See the above attachment '