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One mole of an organic amide (A) on alkaline hydrolysis gives one mole of `NH_(3)` and one mole of a monobasic acid of equivalent mass 74. What is the molecular mass of (A) ? |
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Answer» `R-overset(O)overset(||)C-NH_(2)+OH^(-)toR-overset(O)overset(||)C-O^(-)+NH_(3)` R+45=74orR=29i.e., `CH_(3)CH_(2)-` Monobsic acid=`CH_(3)CH_(2)COOH,` Mol. Mass=`CH_(3)CH_(2)CONH_(2)=73` |
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